Which equation represents a line that passes through (4, left-parenthesis 4, StartFraction one-third EndFraction right-parenthesis.) and has a slope of StartFraction 3 Over 4 EndFraction.? y – y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis. = y minus StartFraction 3 Over 4 EndFraction equals StartFraction one-third EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4) y – y minus StartFraction one-third EndFraction equals 4 left-parenthesis x minus StartFraction 3 Over 4 EndFraction right-parenthesis. = y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4) y – y minus StartFraction one-third EndFraction equals 4 left-parenthesis x minus StartFraction 3 Over 4 EndFraction right-parenthesis. = 4(x – ) y – 4 = y minus 4 equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus StartFraction one-third EndFraction right-parenthesis.(x – )

The equation which represents a line passes through point (4 , [tex]\frac{1}{3}[/tex] ) and has slope [tex]\frac{3}{4}[/tex] is   [tex]y-\frac{1}{3}=\frac{3}{4}(x-4)[/tex] ⇒ 1stStep-by-step explanation:The line passes through point (4 , [tex]\frac{1}{3}[/tex] ) and has slope [tex]\frac{3}{4}[/tex]The form of the equation of a line has slope m and passes through point [tex](x_{1},y_{1})[/tex] is [tex]y-y_{1}=m(x-x_{1})[/tex]∵ m = [tex]\frac{3}{4}[/tex]∵ [tex](x_{1},y_{1})[/tex] = (4 , [tex]\frac{1}{3}[/tex] )Substitute these values in the form of the equation above∴ The equation of the line is:    [tex]y-\frac{1}{3}=\frac{3}{4}(x-4)[/tex]The four answers are:[tex]y-\frac{1}{3}=\frac{3}{4}(x-4)[/tex][tex]y-\frac{3}{4}=\frac{1}{3}(x-4)[/tex][tex]y-\frac{1}{3}=4(x-\frac{3}{4})[/tex][tex]y-4=\frac{3}{4}(x-\frac{1}{3})[/tex]The right answer is the first one [tex]y-\frac{1}{3}=\frac{3}{4}(x-4)[/tex]Learn more:You can learn more about the equation of a line in brainly.com/question/8955867#LearnwithBrainly