Q:

the graph of y=sinx is reflected on the line x=y then on y=2 the resulting graph has which equation​

Accepted Solution

A:
Answer:y = 4 - sin⁻¹x Step-by-step explanation:1. Reflection about y = x If we reflect a function ƒ(x) about the line y = x, we are creating its inverse, ƒ'(x). Thus, reflection of y = sinx  about y = x gives y = sin⁻¹x. The range of the reflection extends from -∞ to +∞, but the range of the function y = sin⁻¹x is [-π/2, π/2] (see Fig. 1) . 2. Reflection about y = 2 Reflection about y = 2 retains the sign of x but changes the sign of y. Note, however, that in Figure 2 the point at (0, 0) is reflected to (4, 0). The function is translated up by four units. After the two reflections, the equation of the line is y = 4 - sin⁻¹x