[tex]\frac{(x-4)^{2} }{(x+3)(x+1)} [/tex] or [tex]\frac{ x^{2} -8x+16}{ x^{2}+4x+3 }[/tex]
Based on the numerator of the second fraction (since we used its inverse), the denominators of both, and the factors we canceled out earlier, the restrictions are x ≠ -4, -3, -2, -1, 4