MATH SOLVE

3 months ago

Q:
# What is the equation, in slope-intercept form, of the line parallel to βy=5x+2 that passes through the point with coordinates (β2,1)?

Accepted Solution

A:

Answer:Step-by-step explanation:y = 5x + 2Slope- intercept form: y = mx + bParallel lines have same slope.m = 5y = 5x + bNow, line passes through (-2,1). So, plugin these values in the above equation.1 = 5*(-2) + b1 = - 10 + bb = 1 + 10b = 11Equation of the line: y = 5x + 11