MATH SOLVE

3 months ago

Q:
# The ratios of the measures of the sides of a triangle is 4:10:7. Find the length of each side if the perimeter of the triangle is 252 meters.

Accepted Solution

A:

Answer:First side of the triangle = 48 mSecond side = 120 mThird side = 84 mStep-by-step explanation:The ratios of the measures of the sides of a triangle is 4:10:7Let us assume the common ratio of the sides of the triangle = mSo, the first side of the triangle = 4 mSecond side of the triangle = 10 mThird side of the triangle = 7 mNow, PERIMETER OF A TRIANGLE = SUM OF ALL SIDES⇒ 4 m + 10 m + 7 m = 252 mor, 21 m = 252 m⇒ m = 252/ 21 = 12So, the common ratio in the sides is 12.Hence, the first side of the triangle = 4 m = 4 x 12 = 48 mSecond side of the triangle = 10 m = 10 x 12 = 120 mThird side of the triangle = 7 m = 7 x 12 = 84 m